HELLO !!!
  • ADMISSION TO CRASH-2019 FOR JEE, NEET, KPET, VIT, AEEE, FOUNDATION and 2019-20 XI & XII BATCHES STARTED. CONTACT OFFICE
  • USE YOUR MOBILE PHONE TO WRITE ONLINE TEST.
  • STUDENTS and PARENTS CAN DOWNLOAD 'SPEC' APPLICATION FROM GOOGLE PLAY STORE.
  • FOUR NEW JEE MAINS FULL MODEL TEST PAPERS ARE ADDED. ALL STUDENTS OF CLASS XII & REPEATER BATCH ARE REQUESTED TO WRITE THE TESTS.
  • ALL STUDENTS ARE REQUESTED TO TRY SELF TEST AFTER COMPLETING EACH TOPIC !
  • REGISTRATION FOR ALL COURSES OF 2019-2020-2021 STARTED.
  • PARENTS ARE REQUESTED TO MONITOR ONLINE TEST FOR THEIR WARDS THROUGH THE LOGIN PAGE WHICH IS A NEW ADDITION
  • CONGRATS TO ALL QUALIFIED FOR JEE ADVANCED - 2018, ESPECIALLY TO VAIBHAV JAYASANKAR & M M DEVADEVAN
S P E C provide every facility now available in the globe to its students.
St. Paul Education Centre (SPEC) is a temple where the students can learn without fear. a temple where the students can achieve their goal with full confidence .
STARTS ON 07-10-2018
We, in SPEC, never project tall claims but we train our students to achieve their best.
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    Q 22
    ONLINE EXAM CODE, SUB, etc.
    Posted by
    SPEC
    On 21-02-2017
    Answer

    Q 21
    Sir, will you please solve the problem attached below
    click to see the attachment
    Posted by
    laxmi nag
    On 15-02-2017
    Answer

    Your question has typographical errors. First , it is n = k, if so the sum = e (logx)24


    Second, if n = k and 24 = n=k, then sum = eln x = x (the base of log is taken for granted as e !)

    Q 11
    Sir, the derivative of a function is the fractional change in dependant variable with respect to an independent variable. So if the derivative is zero that means there is no change in the dependant variable. y1-y2 = 0 for two values defined at x1 and x2. So how can we define a tangent at such a point since it could be at any of the point x1 or x2 ?
    Posted by
    George
    On 02-07-2015
    Answer

    Tangent will be a straight line parallel to x-axis. Its equation is y = y1 or y = y2

    Q 8
    Sunny sir can you please give me the exam code of first year vacation paper.
    Posted by
    Joseph C Steephen
    On 13-04-2015
    Answer

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