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  • SECOND YEAR CLASSES WILL BE RESUMED ON 29-04-2019 (MONDAY) AT 7: 00 am
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  • REGISTRATION FOR ALL COURSES OF 2019-2020-2021 STARTED.
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    Q 21
    Sir, will you please solve the problem attached below
    click to see the attachment
    Posted by
    laxmi nag
    On 15-02-2017
    Answer

    Your question has typographical errors. First , it is n = k, if so the sum = e (logx)24


    Second, if n = k and 24 = n=k, then sum = eln x = x (the base of log is taken for granted as e !)
    Q 11
    Sir, the derivative of a function is the fractional change in dependant variable with respect to an independent variable. So if the derivative is zero that means there is no change in the dependant variable. y1-y2 = 0 for two values defined at x1 and x2. So how can we define a tangent at such a point since it could be at any of the point x1 or x2 ?
    Posted by
    George
    On 02-07-2015
    Answer

    Tangent will be a straight line parallel to x-axis. Its equation is y = y1 or y = y2
    Q 6
    Can you please solve the problem I have attached Sub: Physics
    click to see the attachment
    Posted by
    Soju John
    On 21-03-2015
    Answer

    See the answer file attached

    click to see the attachment
    Q 3
    SUNNY SIR'S LIVE CLASS IN VICTERS WAS VERY FRUITFUL....THNKYOU SIR
    Posted by
    sarath k
    On 16-02-2015
    Answer

    Thanks
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