HELLO !!!
  • CRASH BATCH STARTS ON TUESDAY, 19th MARCH -2019 FROM 7:00 am TO 1:30 pm. TAKE ADMISSION BEFORE 19th
  • ADMISSION TO CRASH-2019 FOR JEE, NEET, KPET, VIT, AEEE, FOUNDATION and 2019-20 XI & XII BATCHES STARTED. CONTACT OFFICE
  • USE YOUR MOBILE SMART PHONE TO WRITE ONLINE TEST.
  • STUDENTS and PARENTS CAN DOWNLOAD 'SPEC' APPLICATION FROM GOOGLE PLAY STORE.
  • MANY NEW JEE MAINS FULL MODEL AND SUBLECT WISE TEST PAPERS ARE ADDED . ALL STUDENTS OF CLASS XII & REPEATER BATCH ARE REQUESTED TO WRITE THE TESTS.
  • BLESSING CEREMONY-2019 ,FOR CLASS XII & REPEATER, WILL BE HELD ON 05-01-2019 (SATURDAY) AT 10:00 AM
  • ALL STUDENTS ARE REQUESTED TO TRY SELF TEST AFTER COMPLETING EACH TOPIC !
  • REGISTRATION FOR ALL COURSES OF 2019-2020-2021 STARTED.
  • PARENTS ARE REQUESTED TO MONITOR ONLINE TEST FOR THEIR WARDS THROUGH THE LOGIN PAGE WHICH IS A NEW ADDITION
  • CONGRATS TO ALL QUALIFIED FOR JEE ADVANCED - 2018, ESPECIALLY TO VAIBHAV JAYASANKAR & M M DEVADEVAN
St. PAUL EDUCATION CENTRE
Mail Us ! spectcr@gmail.com
Contact Us ! 9847920322
We Are Open ! 6:30 am To 6:30pm
S P E C provide every facility now available in the globe to its students.
St. Paul Education Centre (SPEC) is a temple where the students can learn without fear. a temple where the students can achieve their goal with full confidence .
Read More
STARTS ON 07-10-2018
Read More
We, in SPEC, never project tall claims but we train our students to achieve their best.
Read More
DOWNLOAD SOLUTIONS
Student/Parent Login
St. Paul Education Centre (SPEC)
CLASS ROOM
Post Your Doubts Below
    No File Choosen Max File Size:2MB
    Q 21
    Sir, will you please solve the problem attached below
    click to see the attachment
    Posted by
    laxmi nag
    On 15-02-2017
    Answer

    Your question has typographical errors. First , it is n = k, if so the sum = e (logx)24


    Second, if n = k and 24 = n=k, then sum = eln x = x (the base of log is taken for granted as e !)
    Q 11
    Sir, the derivative of a function is the fractional change in dependant variable with respect to an independent variable. So if the derivative is zero that means there is no change in the dependant variable. y1-y2 = 0 for two values defined at x1 and x2. So how can we define a tangent at such a point since it could be at any of the point x1 or x2 ?
    Posted by
    George
    On 02-07-2015
    Answer

    Tangent will be a straight line parallel to x-axis. Its equation is y = y1 or y = y2
    Q 8
    Sunny sir can you please give me the exam code of first year vacation paper.
    Posted by
    Joseph C Steephen
    On 13-04-2015
    Answer

    see the news section
    Q 6
    Can you please solve the problem I have attached Sub: Physics
    click to see the attachment
    Posted by
    Soju John
    On 21-03-2015
    Answer

    See the answer file attached

    click to see the attachment
    our gallery
    view more
    Back To Top