HELLO !!!
  • FIRST YEAR CLASS (PLUS ONE) 2019-20 BATCH WILL BE STARTED ON 22-05-2019 WEDNESDAY AT 7:00 am
  • ADMISSION TO CLASS XI , XII & REPEATER (2019-2020) BATCHES STARTED. CONTACT OFFICE
  • USE YOUR MOBILE SMART PHONE TO WRITE ONLINE TEST.
  • STUDENTS and PARENTS CAN DOWNLOAD 'SPEC' APPLICATION FROM GOOGLE PLAY STORE.
  • ALL STUDENTS ARE REQUESTED TO TRY SELF TEST AFTER COMPLETING EACH TOPIC !
  • REGISTRATION FOR ALL COURSES OF 2019-2020-2021 STARTED.
  • PARENTS ARE REQUESTED TO MONITOR ONLINE TEST FOR THEIR WARDS THROUGH THE LOGIN PAGE WHICH IS A NEW ADDITION
  • CONGRATS TO ALL QUALIFIED FOR JEE ADVANCED - 2018, ESPECIALLY TO VAIBHAV JAYASANKAR & M M DEVADEVAN
St. PAUL EDUCATION CENTRE
Mail Us ! spectcr@gmail.com
Contact Us ! 9847920322
We Are Open ! 6:30 am To 6:30pm
S P E C provide every facility now available in the globe to its students.
St. Paul Education Centre (SPEC) is a temple where the students can learn without fear. a temple where the students can achieve their goal with full confidence .
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FIRST YEAR CLASS
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STARTS ON 07-10-2018
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St. Paul Education Centre (SPEC)
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    Q 25
    ANSWER KEY-DIFFERENTIATION-604
    Posted by
    SPEC
    On 10-08-2019
    Answer

    ANSWER KEY -DIFFERENTIATION- 604

    click to see the attachment
    Q 24
    ANSWER KEY OF SECOND YEAR BATCH TESTS TILL 06-07-2019
    Posted by
    SPEC
    On 15-06-2019
    Answer

    ANSWER KEY OF SECOND YEAR BATCH TESTS TILL 06-07-2019

    click to see the attachment
    Q 21
    Sir, will you please solve the problem attached below
    click to see the attachment
    Posted by
    laxmi nag
    On 15-02-2017
    Answer

    Your question has typographical errors. First , it is n = k, if so the sum = e (logx)24


    Second, if n = k and 24 = n=k, then sum = eln x = x (the base of log is taken for granted as e !)
    Q 11
    Sir, the derivative of a function is the fractional change in dependant variable with respect to an independent variable. So if the derivative is zero that means there is no change in the dependant variable. y1-y2 = 0 for two values defined at x1 and x2. So how can we define a tangent at such a point since it could be at any of the point x1 or x2 ?
    Posted by
    George
    On 02-07-2015
    Answer

    Tangent will be a straight line parallel to x-axis. Its equation is y = y1 or y = y2
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